(8x^2+6x-2)-(3x^2-7x+5)=(8x^2+6x-2)

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Solution for (8x^2+6x-2)-(3x^2-7x+5)=(8x^2+6x-2) equation: 



(8x^2+6x-2)-(3x^2-7x+5)=(8x^2+6x-2)

We move all terms to the left:

(8x^2+6x-2)-(3x^2-7x+5)-((8x^2+6x-2))=0

We get rid of parentheses

8x^2-3x^2+6x+7x-((8x^2+6x-2))-2-5=0



We calculate terms in parentheses: -((8x^2+6x-2)), so:

(8x^2+6x-2)

We get rid of parentheses

8x^2+6x-2

Back to the equation:

-(8x^2+6x-2)



We add all the numbers together, and all the variables

5x^2+13x-(8x^2+6x-2)-7=0

We get rid of parentheses

5x^2-8x^2+13x-6x+2-7=0

We add all the numbers together, and all the variables

-3x^2+7x-5=0

a = -3; b = 7; c = -5;
Δ = b2-4ac
Δ = 72-4·(-3)·(-5)
Δ = -11
Delta is less than zero, so there is no solution for the equation

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